1131013201333 has 4 divisors (see below), whose sum is σ = 1131592912768. Its totient is φ = 1130433489900.

The previous prime is 1131013201309. The next prime is 1131013201361. The reversal of 1131013201333 is 3331023101311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1131013201333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131013201363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289852791 + ... + 289856692.

It is an arithmetic number, because the mean of its divisors is an integer number (282898228192).

Almost surely, 2^{1131013201333} is an apocalyptic number.

It is an amenable number.

1131013201333 is a deficient number, since it is larger than the sum of its proper divisors (579711435).

1131013201333 is an equidigital number, since it uses as much as digits as its factorization.

1131013201333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 579711434.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 1131013201333 its reverse (3331023101311), we get a palindrome (4462036302644).

The spelling of 1131013201333 in words is "one trillion, one hundred thirty-one billion, thirteen million, two hundred one thousand, three hundred thirty-three".