1131013312133 has 4 divisors (see below), whose sum is σ = 1131604538988. Its totient is φ = 1130422085280.

The previous prime is 1131013312123. The next prime is 1131013312153. The reversal of 1131013312133 is 3312133101311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 403552726564 + 727460585569 = 635258^2 + 852913^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131013312133 - 2³² = 1126718344837 is a prime.

It is a super-2 number, since 2×1131013312133² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131013312099 and 1131013312108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131013312103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 295610558 + ... + 295614383.

It is an arithmetic number, because the mean of its divisors is an integer number (282901134747).

Almost surely, 2^{1131013312133} is an apocalyptic number.

It is an amenable number.

1131013312133 is a deficient number, since it is larger than the sum of its proper divisors (591226855).

1131013312133 is an equidigital number, since it uses as much as digits as its factorization.

1131013312133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 591226854.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1131013312133 its reverse (3312133101311), we get a palindrome (4443146413444).

The spelling of 1131013312133 in words is "one trillion, one hundred thirty-one billion, thirteen million, three hundred twelve thousand, one hundred thirty-three".