Base | Representation |
---|---|
bin | 10000011101010110000… |
… | …011000001110001101101 |
3 | 11000010100201201201111210 |
4 | 100131112003001301231 |
5 | 122012312112030013 |
6 | 2223330004305033 |
7 | 144466505441634 |
oct | 20352603016155 |
9 | 4003321651453 |
10 | 1131020033133 |
11 | 3a6732361011 |
12 | 1632483a2179 |
13 | 828685a2a73 |
14 | 3ca5519651b |
15 | 1e648e16cc3 |
hex | 107560c1c6d |
1131020033133 has 4 divisors (see below), whose sum is σ = 1508026710848. Its totient is φ = 754013355420.
The previous prime is 1131020033057. The next prime is 1131020033137. The reversal of 1131020033133 is 3313300201311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1131020033133 - 212 = 1131020029037 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131020033137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188503338853 + ... + 188503338858.
It is an arithmetic number, because the mean of its divisors is an integer number (377006677712).
Almost surely, 21131020033133 is an apocalyptic number.
It is an amenable number.
1131020033133 is a deficient number, since it is larger than the sum of its proper divisors (377006677715).
1131020033133 is an equidigital number, since it uses as much as digits as its factorization.
1131020033133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 377006677714.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 1131020033133 its reverse (3313300201311), we get a palindrome (4444320234444).
The spelling of 1131020033133 in words is "one trillion, one hundred thirty-one billion, twenty million, thirty-three thousand, one hundred thirty-three".
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