Base | Representation |
---|---|
bin | 110100101010101101… |
… | …1001010010101110101 |
3 | 101210221021222211121110 |
4 | 1221111123022111311 |
5 | 3323113144131201 |
6 | 123543011305233 |
7 | 11112531653646 |
oct | 1512533122565 |
9 | 353837884543 |
10 | 113102333301 |
11 | 43a6a356031 |
12 | 19b058ab219 |
13 | a886160c99 |
14 | 568d2276cd |
15 | 2e1e6526d6 |
hex | 1a556ca575 |
113102333301 has 4 divisors (see below), whose sum is σ = 150803111072. Its totient is φ = 75401555532.
The previous prime is 113102333299. The next prime is 113102333339. The reversal of 113102333301 is 103333201311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 113102333301 - 21 = 113102333299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113102338301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18850388881 + ... + 18850388886.
It is an arithmetic number, because the mean of its divisors is an integer number (37700777768).
Almost surely, 2113102333301 is an apocalyptic number.
It is an amenable number.
113102333301 is a deficient number, since it is larger than the sum of its proper divisors (37700777771).
113102333301 is an equidigital number, since it uses as much as digits as its factorization.
113102333301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37700777770.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 113102333301 its reverse (103333201311), we get a palindrome (216435534612).
The spelling of 113102333301 in words is "one hundred thirteen billion, one hundred two million, three hundred thirty-three thousand, three hundred one".
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