Base | Representation |
---|---|
bin | 1010010010010110001010… |
… | …0110010110001111110101 |
3 | 1111001020212110200221010010 |
4 | 2210211202212112033311 |
5 | 2440302000044011013 |
6 | 40015514224050433 |
7 | 2245066566122646 |
oct | 244454246261765 |
9 | 44036773627103 |
10 | 11310303110133 |
11 | 3670744279365 |
12 | 1328019763a19 |
13 | 640731989721 |
14 | 2b15c8bbd6cd |
15 | 14931864b7c3 |
hex | a49629963f5 |
11310303110133 has 16 divisors (see below), whose sum is σ = 15119188211840. Its totient is φ = 7520812047936.
The previous prime is 11310303110123. The next prime is 11310303110137. The reversal of 11310303110133 is 33101130301311.
11310303110133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11310303110133 - 225 = 11310269555701 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11310303110137) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23242128 + ... + 23723766.
It is an arithmetic number, because the mean of its divisors is an integer number (944949263240).
Almost surely, 211310303110133 is an apocalyptic number.
It is an amenable number.
11310303110133 is a deficient number, since it is larger than the sum of its proper divisors (3808885101707).
11310303110133 is a wasteful number, since it uses less digits than its factorization.
11310303110133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 501756.
The product of its (nonzero) digits is 243, while the sum is 21.
Adding to 11310303110133 its reverse (33101130301311), we get a palindrome (44411433411444).
The spelling of 11310303110133 in words is "eleven trillion, three hundred ten billion, three hundred three million, one hundred ten thousand, one hundred thirty-three".
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