1131031444131 has 12 divisors (see below), whose sum is σ = 1664536843008. Its totient is φ = 739794151824.

The previous prime is 1131031444009. The next prime is 1131031444241. The reversal of 1131031444131 is 1314441301311.

1131031444131 is a `hidden beast` number, since 1 + 1 + 3 + 103 + 144 + 413 + 1 = 666.

It is not a de Polignac number, because 1131031444131 - 2³⁷ = 993592490659 is a prime.

It is a super-2 number, since 2×1131031444131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131031444095 and 1131031444104.

It is not an unprimeable number, because it can be changed into a prime (1131031444831) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1185567075 + ... + 1185568028.

It is an arithmetic number, because the mean of its divisors is an integer number (138711403584).

Almost surely, 2^{1131031444131} is an apocalyptic number.

1131031444131 is a deficient number, since it is larger than the sum of its proper divisors (533505398877).

1131031444131 is a wasteful number, since it uses less digits than its factorization.

1131031444131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2371135162 (or 2371135159 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 1131031444131 its reverse (1314441301311), we get a palindrome (2445472745442).

The spelling of 1131031444131 in words is "one trillion, one hundred thirty-one billion, thirty-one million, four hundred forty-four thousand, one hundred thirty-one".