1131032113301 has 4 divisors (see below), whose sum is σ = 1132587866592. Its totient is φ = 1129476360012.

The previous prime is 1131032113231. The next prime is 1131032113331. The reversal of 1131032113301 is 1033112301311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1131032113301 - 2¹⁴ = 1131032096917 is a prime.

It is a super-2 number, since 2×1131032113301² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131032113331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 777875555 + ... + 777877008.

It is an arithmetic number, because the mean of its divisors is an integer number (283146966648).

Almost surely, 2^{1131032113301} is an apocalyptic number.

It is an amenable number.

1131032113301 is a deficient number, since it is larger than the sum of its proper divisors (1555753291).

1131032113301 is an equidigital number, since it uses as much as digits as its factorization.

1131032113301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1555753290.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1131032113301 its reverse (1033112301311), we get a palindrome (2164144414612).

The spelling of 1131032113301 in words is "one trillion, one hundred thirty-one billion, thirty-two million, one hundred thirteen thousand, three hundred one".