Base | Representation |
---|---|
bin | 11001101101110111100101… |
… | …111110010001100111100010 |
3 | 112211110120012201020202111022 |
4 | 121231313211332101213202 |
5 | 104311040404410104442 |
6 | 1040314524005445442 |
7 | 32552303346331526 |
oct | 3155674576214742 |
9 | 484416181222438 |
10 | 113103232113122 |
11 | 330468a1a29439 |
12 | 108281b7710882 |
13 | 4b15787114364 |
14 | 1dd0323241d86 |
15 | d1211bcd43d2 |
hex | 66dde5f919e2 |
113103232113122 has 8 divisors (see below), whose sum is σ = 170200362151872. Its totient is φ = 56369778062500.
The previous prime is 113103232112989. The next prime is 113103232113163. The reversal of 113103232113122 is 221311232301311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×1131032321131222 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113103232113091 and 113103232113100.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90918996254 + ... + 90918997497.
It is an arithmetic number, because the mean of its divisors is an integer number (21275045268984).
Almost surely, 2113103232113122 is an apocalyptic number.
113103232113122 is a deficient number, since it is larger than the sum of its proper divisors (57097130038750).
113103232113122 is a wasteful number, since it uses less digits than its factorization.
113103232113122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 181837994064.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 113103232113122 its reverse (221311232301311), we get a palindrome (334414464414433).
The spelling of 113103232113122 in words is "one hundred thirteen trillion, one hundred three billion, two hundred thirty-two million, one hundred thirteen thousand, one hundred twenty-two".
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