Base | Representation |
---|---|
bin | 10000011101010110110… |
… | …001111001110100101011 |
3 | 11000010101120212000201221 |
4 | 100131112301321310223 |
5 | 122012323233240243 |
6 | 2223331123522511 |
7 | 144500015051362 |
oct | 20352661716453 |
9 | 4003346760657 |
10 | 1131032321323 |
11 | 3a6739294343 |
12 | 163250529437 |
13 | 8286acb5c98 |
14 | 3ca56a747d9 |
15 | 1e64a042bed |
hex | 10756c79d2b |
1131032321323 has 4 divisors (see below), whose sum is σ = 1197563634360. Its totient is φ = 1064501008288.
The previous prime is 1131032321299. The next prime is 1131032321411. The reversal of 1131032321323 is 3231232301311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131032321323 is a prime.
It is a super-2 number, since 2×11310323213232 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1131032321723) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33265656493 + ... + 33265656526.
It is an arithmetic number, because the mean of its divisors is an integer number (299390908590).
Almost surely, 21131032321323 is an apocalyptic number.
1131032321323 is a deficient number, since it is larger than the sum of its proper divisors (66531313037).
1131032321323 is an equidigital number, since it uses as much as digits as its factorization.
1131032321323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66531313036.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1131032321323 its reverse (3231232301311), we get a palindrome (4362264622634).
The spelling of 1131032321323 in words is "one trillion, one hundred thirty-one billion, thirty-two million, three hundred twenty-one thousand, three hundred twenty-three".
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