Base | Representation |
---|---|
bin | 10000011101010111010… |
… | …000101110011110011111 |
3 | 11000010102011001112101202 |
4 | 100131113100232132133 |
5 | 122012332320320221 |
6 | 2223332013030115 |
7 | 144500143533242 |
oct | 20352720563637 |
9 | 4003364045352 |
10 | 1131040401311 |
11 | 3a6742902a17 |
12 | 16325318533b |
13 | 8286c884942 |
14 | 3ca57b79259 |
15 | 1e64aadbd0b |
hex | 1075742e79f |
1131040401311 has 8 divisors (see below), whose sum is σ = 1131491681280. Its totient is φ = 1130589221112.
The previous prime is 1131040401289. The next prime is 1131040401319.
1131040401311 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1131040401311 - 218 = 1131040139167 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131040401319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28922870 + ... + 28961948.
It is an arithmetic number, because the mean of its divisors is an integer number (141436460160).
Almost surely, 21131040401311 is an apocalyptic number.
1131040401311 is a deficient number, since it is larger than the sum of its proper divisors (451279969).
1131040401311 is an equidigital number, since it uses as much as digits as its factorization.
1131040401311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49885.
The product of its (nonzero) digits is 144, while the sum is 20.
It can be divided in two parts, 1131040 and 401311, that added together give a palindrome (1532351).
The spelling of 1131040401311 in words is "one trillion, one hundred thirty-one billion, forty million, four hundred one thousand, three hundred eleven".
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