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113104151 = 313648521
BaseRepresentation
bin1101011110111…
…01010100010111
321212211021201122
412233131110113
5212423313101
615120114155
72542240466
oct657352427
9255737648
10113104151
1158931906
1231a6595b
131a581244
14110429dd
159de251b
hex6bdd517

113104151 has 4 divisors (see below), whose sum is σ = 116752704. Its totient is φ = 109455600.

The previous prime is 113104141. The next prime is 113104163. The reversal of 113104151 is 151401311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 151401311 = 617245383.

It is a cyclic number.

It is not a de Polignac number, because 113104151 - 210 = 113103127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113104141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1824230 + ... + 1824291.

It is an arithmetic number, because the mean of its divisors is an integer number (29188176).

Almost surely, 2113104151 is an apocalyptic number.

113104151 is a deficient number, since it is larger than the sum of its proper divisors (3648553).

113104151 is an equidigital number, since it uses as much as digits as its factorization.

113104151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3648552.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 113104151 is about 10635.0435354069. The cubic root of 113104151 is about 483.6073001945.

Adding to 113104151 its reverse (151401311), we get a palindrome (264505462).

The spelling of 113104151 in words is "one hundred thirteen million, one hundred four thousand, one hundred fifty-one".

Divisors: 1 31 3648521 113104151