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113104234151 = 195952854429
BaseRepresentation
bin110100101010110001…
…0011010011010100111
3101210221102120102002022
41221111202122122213
53323114140443101
6123543120133355
711112554061536
oct1512542323247
9353842512068
10113104234151
1143a70434187
1219b0646725b
13a88667824c
14568d5a031d
152e1e8caa1b
hex1a5589a6a7

113104234151 has 4 divisors (see below), whose sum is σ = 119057088600. Its totient is φ = 107151379704.

The previous prime is 113104234147. The next prime is 113104234157. The reversal of 113104234151 is 151432401311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113104234151 - 22 = 113104234147 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113104234151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113104234157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2976427196 + ... + 2976427233.

It is an arithmetic number, because the mean of its divisors is an integer number (29764272150).

Almost surely, 2113104234151 is an apocalyptic number.

113104234151 is a deficient number, since it is larger than the sum of its proper divisors (5952854449).

113104234151 is an equidigital number, since it uses as much as digits as its factorization.

113104234151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5952854448.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 113104234151 its reverse (151432401311), we get a palindrome (264536635462).

The spelling of 113104234151 in words is "one hundred thirteen billion, one hundred four million, two hundred thirty-four thousand, one hundred fifty-one".

Divisors: 1 19 5952854429 113104234151