1131042433131 has 24 divisors (see below), whose sum is σ = 1759478338800. Its totient is φ = 695994860736.

The previous prime is 1131042433121. The next prime is 1131042433159. The reversal of 1131042433131 is 1313342401311.

1131042433131 is a `hidden beast` number, since 1 + 1 + 3 + 104 + 243 + 313 + 1 = 666.

It is not a de Polignac number, because 1131042433131 - 2⁵ = 1131042433099 is a prime.

It is a super-2 number, since 2×1131042433131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131042433095 and 1131042433104.

It is not an unprimeable number, because it can be changed into a prime (1131042433111) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2549980 + ... + 2960486.

It is an arithmetic number, because the mean of its divisors is an integer number (73311597450).

Almost surely, 2^{1131042433131} is an apocalyptic number.

1131042433131 is a deficient number, since it is larger than the sum of its proper divisors (628435905669).

1131042433131 is a wasteful number, since it uses less digits than its factorization.

1131042433131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 434075 (or 434072 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 1131042433131 its reverse (1313342401311), we get a palindrome (2444384834442).

The spelling of 1131042433131 in words is "one trillion, one hundred thirty-one billion, forty-two million, four hundred thirty-three thousand, one hundred thirty-one".