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113104512000 = 210345310909
BaseRepresentation
bin110100101010110001…
…1011110010000000000
3101210221110002112020000
41221111203132100000
53323114223341000
6123543130120000
711112556326564
oct1512543362000
9353843075200
10113104512000
1143a70603a07
1219b06580000
13a88674485c
14568d6336a4
152e1e933000
hex1a558de400

113104512000 has 440 divisors, whose sum is σ = 421553366520. Its totient is φ = 30158438400.

The previous prime is 113104511999. The next prime is 113104512029. The reversal of 113104512000 is 215401311.

113104512000 is a `hidden beast` number, since 1 + 1 + 3 + 10 + 451 + 200 + 0 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 13470852096 + 99633659904 = 116064^2 + 315648^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 10362546 + ... + 10373454.

It is an arithmetic number, because the mean of its divisors is an integer number (958075833).

Almost surely, 2113104512000 is an apocalyptic number.

113104512000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113104512000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (210776683260).

113104512000 is an abundant number, since it is smaller than the sum of its proper divisors (308448854520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113104512000 is an equidigital number, since it uses as much as digits as its factorization.

113104512000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10956 (or 10919 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

Adding to 113104512000 its reverse (215401311), we get a palindrome (113319913311).

The spelling of 113104512000 in words is "one hundred thirteen billion, one hundred four million, five hundred twelve thousand".