11311010223433 has 4 divisors (see below), whose sum is σ = 11311284265108. Its totient is φ = 11310736181760.

The previous prime is 11311010223377. The next prime is 11311010223473. The reversal of 11311010223433 is 33432201011311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1863421565184 + 9447588658249 = 1365072^2 + 3073693^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11311010223433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311010223398 and 11311010223407.

It is not an unprimeable number, because it can be changed into a prime (11311010223473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136958916 + ... + 137041477.

It is an arithmetic number, because the mean of its divisors is an integer number (2827821066277).

Almost surely, 2^{11311010223433} is an apocalyptic number.

It is an amenable number.

11311010223433 is a deficient number, since it is larger than the sum of its proper divisors (274041675).

11311010223433 is an equidigital number, since it uses as much as digits as its factorization.

11311010223433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 274041674.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 11311010223433 its reverse (33432201011311), we get a palindrome (44743211234744).

The spelling of 11311010223433 in words is "eleven trillion, three hundred eleven billion, ten million, two hundred twenty-three thousand, four hundred thirty-three".