Base | Representation |
---|---|
bin | 1010010010011001001001… |
… | …0001101100101010100111 |
3 | 1111001022221012211201021002 |
4 | 2210212102101230222213 |
5 | 2440310114332101203 |
6 | 40020125440343515 |
7 | 2245125451113005 |
oct | 244462221545247 |
9 | 44038835751232 |
10 | 11311103003303 |
11 | 36710148469a4 |
12 | 1328201614b9b |
13 | 64082b602aac |
14 | 2b166311ba75 |
15 | 1493639a1d88 |
hex | a499246caa7 |
11311103003303 has 4 divisors (see below), whose sum is σ = 11335323781080. Its totient is φ = 11286882225528.
The previous prime is 11311103003273. The next prime is 11311103003329. The reversal of 11311103003303 is 30330030111311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11311103003303 - 210 = 11311103002279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11311103003353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12110388188 + ... + 12110389121.
It is an arithmetic number, because the mean of its divisors is an integer number (2833830945270).
Almost surely, 211311103003303 is an apocalyptic number.
11311103003303 is a deficient number, since it is larger than the sum of its proper divisors (24220777777).
11311103003303 is an equidigital number, since it uses as much as digits as its factorization.
11311103003303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24220777776.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 11311103003303 its reverse (30330030111311), we get a palindrome (41641133114614).
The spelling of 11311103003303 in words is "eleven trillion, three hundred eleven billion, one hundred three million, three thousand, three hundred three".
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