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113111401135 = 571931463533
BaseRepresentation
bin110100101010111110…
…1110000001010101111
3101210221221001112100011
41221111331300022233
53323123004314020
6123543533514051
711113002021535
oct1512575601257
9353857045304
10113111401135
1143a74489907
1219b08942927
13a887cb7475
145690508155
152e2034435a
hex1a55f702af

113111401135 has 8 divisors (see below), whose sum is σ = 135922466880. Its totient is φ = 90363263904.

The previous prime is 113111401133. The next prime is 113111401171. The reversal of 113111401135 is 531104111311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113111401135 - 21 = 113111401133 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113111401133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15728172 + ... + 15735361.

It is an arithmetic number, because the mean of its divisors is an integer number (16990308360).

Almost surely, 2113111401135 is an apocalyptic number.

113111401135 is a deficient number, since it is larger than the sum of its proper divisors (22811065745).

113111401135 is an equidigital number, since it uses as much as digits as its factorization.

113111401135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31464257.

The product of its (nonzero) digits is 180, while the sum is 22.

Adding to 113111401135 its reverse (531104111311), we get a palindrome (644215512446).

The spelling of 113111401135 in words is "one hundred thirteen billion, one hundred eleven million, four hundred one thousand, one hundred thirty-five".

Divisors: 1 5 719 3595 31463533 157317665 22622280227 113111401135