Base | Representation |
---|---|
bin | 10000011101011011101… |
… | …001100110100011011011 |
3 | 11000010121021121022210020 |
4 | 100131123221212203123 |
5 | 122013010143000243 |
6 | 2223343203121523 |
7 | 144502026426063 |
oct | 20353351464333 |
9 | 4003537538706 |
10 | 1131114031323 |
11 | 3a6780423271 |
12 | 1632739732a3 |
13 | 82881bc47b3 |
14 | 3ca638643a3 |
15 | 1e6522d3283 |
hex | 1075ba668db |
1131114031323 has 8 divisors (see below), whose sum is σ = 1508260761600. Its totient is φ = 754021660968.
The previous prime is 1131114031283. The next prime is 1131114031361. The reversal of 1131114031323 is 3231304111311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1131114031323 - 213 = 1131114023131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1131114031293 and 1131114031302.
It is not an unprimeable number, because it can be changed into a prime (1131114031423) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13541403 + ... + 13624676.
It is an arithmetic number, because the mean of its divisors is an integer number (188532595200).
Almost surely, 21131114031323 is an apocalyptic number.
1131114031323 is a deficient number, since it is larger than the sum of its proper divisors (377146730277).
1131114031323 is a wasteful number, since it uses less digits than its factorization.
1131114031323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27179961.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 1131114031323 its reverse (3231304111311), we get a palindrome (4362418142634).
The spelling of 1131114031323 in words is "one trillion, one hundred thirty-one billion, one hundred fourteen million, thirty-one thousand, three hundred twenty-three".
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