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113111511340423 = 454772924872087
BaseRepresentation
bin11001101101111111010011…
…011101000001010110000111
3112211111100120201002002020111
4121231333103131001112013
5104311204333400343143
61040322413322213451
732553015460523461
oct3155772335012607
9484440521062214
10113111511340423
113304a360382452
1210829928354287
134b164a646121b
141dd08aaa33131
15d12453a8899d
hex66dfd3741587

113111511340423 has 4 divisors (see below), whose sum is σ = 113111540760240. Its totient is φ = 113111481920608.

The previous prime is 113111511340403. The next prime is 113111511340427. The reversal of 113111511340423 is 324043115111311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113111511340423 - 213 = 113111511332231 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113111511340427) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7888315 + ... + 16983772.

It is an arithmetic number, because the mean of its divisors is an integer number (28277885190060).

Almost surely, 2113111511340423 is an apocalyptic number.

113111511340423 is a deficient number, since it is larger than the sum of its proper divisors (29419817).

113111511340423 is an equidigital number, since it uses as much as digits as its factorization.

113111511340423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29419816.

The product of its (nonzero) digits is 4320, while the sum is 31.

Adding to 113111511340423 its reverse (324043115111311), we get a palindrome (437154626451734).

The spelling of 113111511340423 in words is "one hundred thirteen trillion, one hundred eleven billion, five hundred eleven million, three hundred forty thousand, four hundred twenty-three".

Divisors: 1 4547729 24872087 113111511340423