11311183806343 has 4 divisors (see below), whose sum is σ = 11344748150320. Its totient is φ = 11277619462368.

The previous prime is 11311183806331. The next prime is 11311183806401. The reversal of 11311183806343 is 34360838111311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11311183806343 is a prime.

It is a super-3 number, since 3×11311183806343³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11311183806343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311181806343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16782171483 + ... + 16782172156.

It is an arithmetic number, because the mean of its divisors is an integer number (2836187037580).

Almost surely, 2^{11311183806343} is an apocalyptic number.

11311183806343 is a deficient number, since it is larger than the sum of its proper divisors (33564343977).

11311183806343 is an equidigital number, since it uses as much as digits as its factorization.

11311183806343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33564343976.

The product of its (nonzero) digits is 124416, while the sum is 43.

The spelling of 11311183806343 in words is "eleven trillion, three hundred eleven billion, one hundred eighty-three million, eight hundred six thousand, three hundred forty-three".