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113112030103 = 3892593112139
BaseRepresentation
bin110100101011000000…
…0001001101110010111
3101210221222020111010021
41221112000021232113
53323123134430403
6123543555210011
711113010251342
oct1512600115627
9353858214107
10113112030103
1143a74879416
1219b08ba6907
13a888177837
14569062d459
152e2041a8bd
hex1a56009b97

113112030103 has 8 divisors (see below), whose sum is σ = 113447552400. Its totient is φ = 112776738048.

The previous prime is 113112030049. The next prime is 113112030107. The reversal of 113112030103 is 301030211311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113112030103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113112030107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 952608 + ... + 1064746.

It is an arithmetic number, because the mean of its divisors is an integer number (14180944050).

Almost surely, 2113112030103 is an apocalyptic number.

113112030103 is a deficient number, since it is larger than the sum of its proper divisors (335522297).

113112030103 is a wasteful number, since it uses less digits than its factorization.

113112030103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 115121.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 113112030103 its reverse (301030211311), we get a palindrome (414142241414).

The spelling of 113112030103 in words is "one hundred thirteen billion, one hundred twelve million, thirty thousand, one hundred three".

Divisors: 1 389 2593 112139 1008677 43622071 290776427 113112030103