113112112200103 has 4 divisors (see below), whose sum is σ = 113112326987568. Its totient is φ = 113111897412640.

The previous prime is 113112112200091. The next prime is 113112112200107. The reversal of 113112112200103 is 301002211211311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113112112200103 is a prime.

It is a super-2 number, since 2×113112112200103² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113112112200107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106601851 + ... + 107657692.

It is an arithmetic number, because the mean of its divisors is an integer number (28278081746892).

Almost surely, 2^{113112112200103} is an apocalyptic number.

113112112200103 is a deficient number, since it is larger than the sum of its proper divisors (214787465).

113112112200103 is an equidigital number, since it uses as much as digits as its factorization.

113112112200103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 214787464.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 113112112200103 its reverse (301002211211311), we get a palindrome (414114323411414).

The spelling of 113112112200103 in words is "one hundred thirteen trillion, one hundred twelve billion, one hundred twelve million, two hundred thousand, one hundred three".