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113112311121002 = 256556155560501
BaseRepresentation
bin11001101110000000000011…
…000111111100010001101010
3112211111102122110000010221102
4121232000003013330101222
5104311213003121333002
61040323024532241402
732553044341534334
oct3156000307742152
9484442573003842
10113112311121002
113304a730883436
1210829b10170262
134b165a306827b
141dd0944d42454
15d1249ddbaa02
hex66e0031fc46a

113112311121002 has 4 divisors (see below), whose sum is σ = 169668466681506. Its totient is φ = 56556155560500.

The previous prime is 113112311120993. The next prime is 113112311121011. The reversal of 113112311121002 is 200121113211311.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (113112311120993) and next prime (113112311121011).

It can be written as a sum of positive squares in only one way, i.e., 59858089713601 + 53254221407401 = 7736801^2 + 7297549^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28278077780249 + ... + 28278077780252.

Almost surely, 2113112311121002 is an apocalyptic number.

113112311121002 is a deficient number, since it is larger than the sum of its proper divisors (56556155560504).

113112311121002 is an equidigital number, since it uses as much as digits as its factorization.

113112311121002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56556155560503.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 113112311121002 its reverse (200121113211311), we get a palindrome (313233424332313).

The spelling of 113112311121002 in words is "one hundred thirteen trillion, one hundred twelve billion, three hundred eleven million, one hundred twenty-one thousand, two".

Divisors: 1 2 56556155560501 113112311121002