11311302103 has 4 divisors (see below), whose sum is σ = 11676182848. Its totient is φ = 10946421360.

The previous prime is 11311302083. The next prime is 11311302109. The reversal of 11311302103 is 30120311311.

11311302103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11311302103 - 2¹³ = 11311293911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311302109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182440326 + ... + 182440387.

It is an arithmetic number, because the mean of its divisors is an integer number (2919045712).

Almost surely, 2^11311302103 is an apocalyptic number.

11311302103 is a deficient number, since it is larger than the sum of its proper divisors (364880745).

11311302103 is an equidigital number, since it uses as much as digits as its factorization.

11311302103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 364880744.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11311302103 its reverse (30120311311), we get a palindrome (41431613414).

The spelling of 11311302103 in words is "eleven billion, three hundred eleven million, three hundred two thousand, one hundred three".