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1131130331323 = 8313628076281
BaseRepresentation
bin10000011101011100100…
…111110010000010111011
311000010122102021110011221
4100131130213302002323
5122013023331100243
62223344544332511
7144502315114666
oct20353447620273
94003572243157
101131130331323
113a6789646743
12163279314137
13828853b0a75
143ca65aa86dd
151e653952bed
hex1075c9f20bb

1131130331323 has 4 divisors (see below), whose sum is σ = 1144758407688. Its totient is φ = 1117502254960.

The previous prime is 1131130331281. The next prime is 1131130331341. The reversal of 1131130331323 is 3231330311311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131130331323 - 237 = 993691377851 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131130331623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6814038058 + ... + 6814038223.

It is an arithmetic number, because the mean of its divisors is an integer number (286189601922).

Almost surely, 21131130331323 is an apocalyptic number.

1131130331323 is a deficient number, since it is larger than the sum of its proper divisors (13628076365).

1131130331323 is an equidigital number, since it uses as much as digits as its factorization.

1131130331323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13628076364.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1131130331323 its reverse (3231330311311), we get a palindrome (4362460642634).

The spelling of 1131130331323 in words is "one trillion, one hundred thirty-one billion, one hundred thirty million, three hundred thirty-one thousand, three hundred twenty-three".

Divisors: 1 83 13628076281 1131130331323