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113113111313 = 206651547363
BaseRepresentation
bin110100101011000010…
…0010001101100010001
3101210222001021102021002
41221112010101230101
53323123424030223
6123544034311345
711113022403506
oct1512604215421
9353861242232
10113113111313
1143a75447784
1219b09428555
13a8884659c7
1456908314ad
152e20580e28
hex1a56111b11

113113111313 has 4 divisors (see below), whose sum is σ = 113113865328. Its totient is φ = 113112357300.

The previous prime is 113113111261. The next prime is 113113111351. The reversal of 113113111313 is 313111311311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 113113111313 - 210 = 113113110289 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113113111513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67031 + ... + 480332.

It is an arithmetic number, because the mean of its divisors is an integer number (28278466332).

Almost surely, 2113113111313 is an apocalyptic number.

It is an amenable number.

113113111313 is a deficient number, since it is larger than the sum of its proper divisors (754015).

113113111313 is an equidigital number, since it uses as much as digits as its factorization.

113113111313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 754014.

The product of its digits is 81, while the sum is 20.

Adding to 113113111313 its reverse (313111311311), we get a palindrome (426224422624).

The spelling of 113113111313 in words is "one hundred thirteen billion, one hundred thirteen million, one hundred eleven thousand, three hundred thirteen".

Divisors: 1 206651 547363 113113111313