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113113122002 = 269181847411
BaseRepresentation
bin110100101011000010…
…0010100010011010010
3101210222001021221220222
41221112010110103102
53323123424401002
6123544034433042
711113022446616
oct1512604242322
9353861257828
10113113122002
1143a75454811
1219b09432782
13a88846a82a
145690835346
152e205841a2
hex1a561144d2

113113122002 has 8 divisors (see below), whose sum is σ = 169915227312. Its totient is φ = 56474712900.

The previous prime is 113113121999. The next prime is 113113122041. The reversal of 113113122002 is 200221311311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40922324 + ... + 40925087.

It is an arithmetic number, because the mean of its divisors is an integer number (21239403414).

Almost surely, 2113113122002 is an apocalyptic number.

113113122002 is a deficient number, since it is larger than the sum of its proper divisors (56802105310).

113113122002 is an equidigital number, since it uses as much as digits as its factorization.

113113122002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81848104.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 113113122002 its reverse (200221311311), we get a palindrome (313334433313).

It can be divided in two parts, 11311 and 3122002, that added together give a palindrome (3133313).

The spelling of 113113122002 in words is "one hundred thirteen billion, one hundred thirteen million, one hundred twenty-two thousand, two".

Divisors: 1 2 691 1382 81847411 163694822 56556561001 113113122002