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11311312303111 = 40784327734477
BaseRepresentation
bin1010010010011001111011…
…0000000111010000000111
31111001100110210200020121211
42210212132300013100013
52440311031422144421
640020202314352251
72245133602122352
oct244463660072007
944040423606554
1011311312303111
113671111a00a47
12132825b72b687
13640862a95032
142b1682c41299
151493770469e1
hexa499ec07407

11311312303111 has 4 divisors (see below), whose sum is σ = 11311340445432. Its totient is φ = 11311284160792.

The previous prime is 11311312303079. The next prime is 11311312303163. The reversal of 11311312303111 is 11130321311311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11311312303111 - 25 = 11311312303079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311312373111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13459396 + ... + 14275081.

It is an arithmetic number, because the mean of its divisors is an integer number (2827835111358).

Almost surely, 211311312303111 is an apocalyptic number.

11311312303111 is a deficient number, since it is larger than the sum of its proper divisors (28142321).

11311312303111 is an equidigital number, since it uses as much as digits as its factorization.

11311312303111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28142320.

The product of its (nonzero) digits is 162, while the sum is 22.

Adding to 11311312303111 its reverse (11130321311311), we get a palindrome (22441633614422).

The spelling of 11311312303111 in words is "eleven trillion, three hundred eleven billion, three hundred twelve million, three hundred three thousand, one hundred eleven".

Divisors: 1 407843 27734477 11311312303111