Base | Representation |
---|---|
bin | 10000011101011100101… |
… | …011011110100111101101 |
3 | 11000010122111002200102012 |
4 | 100131130223132213231 |
5 | 122013024103102313 |
6 | 2223345021211005 |
7 | 144502326262046 |
oct | 20353453364755 |
9 | 4003574080365 |
10 | 1131131300333 |
11 | 3a678a148781 |
12 | 163279700a65 |
13 | 8288565cb48 |
14 | 3ca65c7b8cd |
15 | 1e653a94da8 |
hex | 1075cade9ed |
1131131300333 has 16 divisors (see below), whose sum is σ = 1141408039680. Its totient is φ = 1120911456000.
The previous prime is 1131131300329. The next prime is 1131131300357. The reversal of 1131131300333 is 3330031311311.
It is a cyclic number.
It is not a de Polignac number, because 1131131300333 - 22 = 1131131300329 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1131131300299 and 1131131300308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131131300323) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52843433 + ... + 52864833.
It is an arithmetic number, because the mean of its divisors is an integer number (71338002480).
Almost surely, 21131131300333 is an apocalyptic number.
It is an amenable number.
1131131300333 is a deficient number, since it is larger than the sum of its proper divisors (10276739347).
1131131300333 is a wasteful number, since it uses less digits than its factorization.
1131131300333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22708.
The product of its (nonzero) digits is 729, while the sum is 23.
Adding to 1131131300333 its reverse (3330031311311), we get a palindrome (4461162611644).
The spelling of 1131131300333 in words is "one trillion, one hundred thirty-one billion, one hundred thirty-one million, three hundred thousand, three hundred thirty-three".
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