113113130133 has 4 divisors (see below), whose sum is σ = 150817506848. Its totient is φ = 75408753420.

The previous prime is 113113130113. The next prime is 113113130161. The reversal of 113113130133 is 331031311311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 113113130133 - 2⁵ = 113113130101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113113130113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18852188353 + ... + 18852188358.

It is an arithmetic number, because the mean of its divisors is an integer number (37704376712).

Almost surely, 2^113113130133 is an apocalyptic number.

It is an amenable number.

113113130133 is a deficient number, since it is larger than the sum of its proper divisors (37704376715).

113113130133 is an equidigital number, since it uses as much as digits as its factorization.

113113130133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37704376714.

The product of its (nonzero) digits is 243, while the sum is 21.

Adding to 113113130133 its reverse (331031311311), we get a palindrome (444144441444).

The spelling of 113113130133 in words is "one hundred thirteen billion, one hundred thirteen million, one hundred thirty thousand, one hundred thirty-three".