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11311313130 = 232513192392129
BaseRepresentation
bin10101000100011010…
…01111000011101010
31002012022020020120100
422202031033003222
5141131144010010
65110224410230
7550206401205
oct124215170352
932168206510
1011311313130
114884a39a77
122238176976
1310b35868c0
1479438a93c
154630852c0
hex2a234f0ea

11311313130 has 192 divisors, whose sum is σ = 33493824000. Its totient is φ = 2625509376.

The previous prime is 11311313107. The next prime is 11311313147. The reversal of 11311313130 is 3131311311.

11311313130 is a `hidden beast` number, since 11 + 311 + 31 + 313 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 5311906 + ... + 5314034.

It is an arithmetic number, because the mean of its divisors is an integer number (174447000).

Almost surely, 211311313130 is an apocalyptic number.

11311313130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11311313130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16746912000).

11311313130 is an abundant number, since it is smaller than the sum of its proper divisors (22182510870).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11311313130 is a wasteful number, since it uses less digits than its factorization.

11311313130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2413 (or 2410 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

Adding to 11311313130 its reverse (3131311311), we get a palindrome (14442624441).

The spelling of 11311313130 in words is "eleven billion, three hundred eleven million, three hundred thirteen thousand, one hundred thirty".