1131133044441 has 4 divisors (see below), whose sum is σ = 1508177392592. Its totient is φ = 754088696292.

The previous prime is 1131133044407. The next prime is 1131133044449. The reversal of 1131133044441 is 1444403311311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1131133044441 - 2⁷ = 1131133044313 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131133044399 and 1131133044408.

It is not an unprimeable number, because it can be changed into a prime (1131133044449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188522174071 + ... + 188522174076.

It is an arithmetic number, because the mean of its divisors is an integer number (377044348148).

Almost surely, 2^{1131133044441} is an apocalyptic number.

It is an amenable number.

1131133044441 is a deficient number, since it is larger than the sum of its proper divisors (377044348151).

1131133044441 is an equidigital number, since it uses as much as digits as its factorization.

1131133044441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 377044348150.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 1131133044441 its reverse (1444403311311), we get a palindrome (2575536355752).

The spelling of 1131133044441 in words is "one trillion, one hundred thirty-one billion, one hundred thirty-three million, forty-four thousand, four hundred forty-one".