11311339035 has 8 divisors (see below), whose sum is σ = 18098142480. Its totient is φ = 6032714144.

The previous prime is 11311339021. The next prime is 11311339057. The reversal of 11311339035 is 53093311311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11311339035 - 2⁵ = 11311339003 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11311338993 and 11311339011.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 377044620 + ... + 377044649.

It is an arithmetic number, because the mean of its divisors is an integer number (2262267810).

Almost surely, 2^11311339035 is an apocalyptic number.

11311339035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11311339035 is a deficient number, since it is larger than the sum of its proper divisors (6786803445).

11311339035 is an equidigital number, since it uses as much as digits as its factorization.

11311339035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 754089277.

The product of its (nonzero) digits is 3645, while the sum is 30.

The spelling of 11311339035 in words is "eleven billion, three hundred eleven million, three hundred thirty-nine thousand, thirty-five".