Base | Representation |
---|---|
bin | 10101000100011011… |
… | …00101010001100011 |
3 | 1002012022101212101202 |
4 | 22202031211101203 |
5 | 141131204413011 |
6 | 5110230351415 |
7 | 550210230416 |
oct | 124215452143 |
9 | 32168355352 |
10 | 11311404131 |
11 | 4884aa1385 |
12 | 22381bb56b |
13 | 10b35b9151 |
14 | 7943b1b7d |
15 | 4630a223b |
hex | 2a2365463 |
11311404131 has 4 divisors (see below), whose sum is σ = 11552072352. Its totient is φ = 11070735912.
The previous prime is 11311404119. The next prime is 11311404133. The reversal of 11311404131 is 13140411311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13140411311 = 479 ⋅27433009.
It is a cyclic number.
It is not a de Polignac number, because 11311404131 - 226 = 11244295267 is a prime.
It is a super-2 number, since 2×113114041312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11311404133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120334040 + ... + 120334133.
It is an arithmetic number, because the mean of its divisors is an integer number (2888018088).
Almost surely, 211311404131 is an apocalyptic number.
11311404131 is a deficient number, since it is larger than the sum of its proper divisors (240668221).
11311404131 is an equidigital number, since it uses as much as digits as its factorization.
11311404131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 240668220.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11311404131 its reverse (13140411311), we get a palindrome (24451815442).
The spelling of 11311404131 in words is "eleven billion, three hundred eleven million, four hundred four thousand, one hundred thirty-one".
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