Base | Representation |
---|---|
bin | 10101000100011011… |
… | …00111000000110101 |
3 | 1002012022102020011112 |
4 | 22202031213000311 |
5 | 141131210130003 |
6 | 5110230444405 |
7 | 550210260242 |
oct | 124215470065 |
9 | 32168366145 |
10 | 11311411253 |
11 | 4884aa676a |
12 | 2238203705 |
13 | 10b35bc46c |
14 | 7943b45c9 |
15 | 4630a43d8 |
hex | 2a2367035 |
11311411253 has 4 divisors (see below), whose sum is σ = 11311940640. Its totient is φ = 11310881868.
The previous prime is 11311411249. The next prime is 11311411283. The reversal of 11311411253 is 35211411311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35211411311 = 61 ⋅577236251.
It is a cyclic number.
It is not a de Polignac number, because 11311411253 - 22 = 11311411249 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11311411283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231233 + ... + 275846.
It is an arithmetic number, because the mean of its divisors is an integer number (2827985160).
Almost surely, 211311411253 is an apocalyptic number.
It is an amenable number.
11311411253 is a deficient number, since it is larger than the sum of its proper divisors (529387).
11311411253 is an equidigital number, since it uses as much as digits as its factorization.
11311411253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 529386.
The product of its digits is 360, while the sum is 23.
Adding to 11311411253 its reverse (35211411311), we get a palindrome (46522822564).
The spelling of 11311411253 in words is "eleven billion, three hundred eleven million, four hundred eleven thousand, two hundred fifty-three".
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