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11311516106355 = 35754101073757
BaseRepresentation
bin1010010010011010101011…
…1001100011111001110011
31111001101000000011112010010
42210212222321203321303
52440311441110400410
640020234434510003
72245141625330043
oct244465271437163
944041000145103
1011311516106355
113671206a51383
1213282b7a35303
1364089608147a
142b16a1d33723
15149389da2c20
hexa49aae63e73

11311516106355 has 8 divisors (see below), whose sum is σ = 18098425770192. Its totient is φ = 6032808590048.

The previous prime is 11311516106347. The next prime is 11311516106393. The reversal of 11311516106355 is 55360161511311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11311516106355 - 23 = 11311516106347 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 377050536864 + ... + 377050536893.

It is an arithmetic number, because the mean of its divisors is an integer number (2262303221274).

Almost surely, 211311516106355 is an apocalyptic number.

11311516106355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11311516106355 is a deficient number, since it is larger than the sum of its proper divisors (6786909663837).

11311516106355 is an equidigital number, since it uses as much as digits as its factorization.

11311516106355 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 754101073765.

The product of its (nonzero) digits is 40500, while the sum is 39.

Adding to 11311516106355 its reverse (55360161511311), we get a palindrome (66671677617666).

The spelling of 11311516106355 in words is "eleven trillion, three hundred eleven billion, five hundred sixteen million, one hundred six thousand, three hundred fifty-five".

Divisors: 1 3 5 15 754101073757 2262303221271 3770505368785 11311516106355