Base | Representation |
---|---|
bin | 1010010010011010101011… |
… | …1001100011111001110011 |
3 | 1111001101000000011112010010 |
4 | 2210212222321203321303 |
5 | 2440311441110400410 |
6 | 40020234434510003 |
7 | 2245141625330043 |
oct | 244465271437163 |
9 | 44041000145103 |
10 | 11311516106355 |
11 | 3671206a51383 |
12 | 13282b7a35303 |
13 | 64089608147a |
14 | 2b16a1d33723 |
15 | 149389da2c20 |
hex | a49aae63e73 |
11311516106355 has 8 divisors (see below), whose sum is σ = 18098425770192. Its totient is φ = 6032808590048.
The previous prime is 11311516106347. The next prime is 11311516106393. The reversal of 11311516106355 is 55360161511311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11311516106355 - 23 = 11311516106347 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 377050536864 + ... + 377050536893.
It is an arithmetic number, because the mean of its divisors is an integer number (2262303221274).
Almost surely, 211311516106355 is an apocalyptic number.
11311516106355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11311516106355 is a deficient number, since it is larger than the sum of its proper divisors (6786909663837).
11311516106355 is an equidigital number, since it uses as much as digits as its factorization.
11311516106355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 754101073765.
The product of its (nonzero) digits is 40500, while the sum is 39.
Adding to 11311516106355 its reverse (55360161511311), we get a palindrome (66671677617666).
The spelling of 11311516106355 in words is "eleven trillion, three hundred eleven billion, five hundred sixteen million, one hundred six thousand, three hundred fifty-five".
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