Base | Representation |
---|---|
bin | 1010010010011010101011… |
… | …1001100011111001101011 |
3 | 1111001101000000011112002211 |
4 | 2210212222321203321223 |
5 | 2440311441110400342 |
6 | 40020234434505551 |
7 | 2245141625330032 |
oct | 244465271437153 |
9 | 44041000145084 |
10 | 11311516106347 |
11 | 3671206a51376 |
12 | 13282b7a352b7 |
13 | 640896081472 |
14 | 2b16a1d33719 |
15 | 149389da2c17 |
hex | a49aae63e6b |
11311516106347 has 2 divisors, whose sum is σ = 11311516106348. Its totient is φ = 11311516106346.
The previous prime is 11311516106339. The next prime is 11311516106393. The reversal of 11311516106347 is 74360161511311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11311516106347 - 23 = 11311516106339 is a prime.
It is not a weakly prime, because it can be changed into another prime (11311516106327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655758053173 + 5655758053174.
It is an arithmetic number, because the mean of its divisors is an integer number (5655758053174).
Almost surely, 211311516106347 is an apocalyptic number.
11311516106347 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311516106347 is an equidigital number, since it uses as much as digits as its factorization.
11311516106347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45360, while the sum is 40.
Adding to 11311516106347 its reverse (74360161511311), we get a palindrome (85671677617658).
The spelling of 11311516106347 in words is "eleven trillion, three hundred eleven billion, five hundred sixteen million, one hundred six thousand, three hundred forty-seven".
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