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113115314113 = 257440137409
BaseRepresentation
bin110100101011000110…
…0101011011111000001
3101210222012102022221021
41221112030223133001
53323130010022423
6123544153425441
711113050206614
oct1512614533701
9353865368837
10113115314113
1143a7671177a
1219b0a10b281
13a888a57539
145690c4617b
152e2086895d
hex1a5632b7c1

113115314113 has 4 divisors (see below), whose sum is σ = 113555451780. Its totient is φ = 112675176448.

The previous prime is 113115314111. The next prime is 113115314149. The reversal of 113115314113 is 311413511311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 101577976369 + 11537337744 = 318713^2 + 107412^2 .

It is a cyclic number.

It is not a de Polignac number, because 113115314113 - 21 = 113115314111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113115314111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220068448 + ... + 220068961.

It is an arithmetic number, because the mean of its divisors is an integer number (28388862945).

Almost surely, 2113115314113 is an apocalyptic number.

It is an amenable number.

113115314113 is a deficient number, since it is larger than the sum of its proper divisors (440137667).

113115314113 is an equidigital number, since it uses as much as digits as its factorization.

113115314113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440137666.

The product of its digits is 540, while the sum is 25.

Adding to 113115314113 its reverse (311413511311), we get a palindrome (424528825424).

The spelling of 113115314113 in words is "one hundred thirteen billion, one hundred fifteen million, three hundred fourteen thousand, one hundred thirteen".

Divisors: 1 257 440137409 113115314113