Base | Representation |
---|---|
bin | 110100101011001111… |
… | …0100110010001000011 |
3 | 101210222112020222022022 |
4 | 1221112132212101003 |
5 | 3323132210330311 |
6 | 123544442232055 |
7 | 11113135142255 |
oct | 1512636462103 |
9 | 353875228268 |
10 | 113120011331 |
11 | 43a7932a878 |
12 | 19b0b7b562b |
13 | a889a10562 |
14 | 5691709cd5 |
15 | 2e20e955db |
hex | 1a567a6443 |
113120011331 has 4 divisors (see below), whose sum is σ = 113481417432. Its totient is φ = 112758605232.
The previous prime is 113120011273. The next prime is 113120011351. The reversal of 113120011331 is 133110021311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 133110021311 = 47 ⋅2832128113.
It is a cyclic number.
It is not a de Polignac number, because 113120011331 - 26 = 113120011267 is a prime.
It is a super-3 number, since 3×1131200113313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113120011351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180702581 + ... + 180703206.
It is an arithmetic number, because the mean of its divisors is an integer number (28370354358).
Almost surely, 2113120011331 is an apocalyptic number.
113120011331 is a deficient number, since it is larger than the sum of its proper divisors (361406101).
113120011331 is an equidigital number, since it uses as much as digits as its factorization.
113120011331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 361406100.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113120011331 its reverse (133110021311), we get a palindrome (246230032642).
The spelling of 113120011331 in words is "one hundred thirteen billion, one hundred twenty million, eleven thousand, three hundred thirty-one".
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