Base | Representation |
---|---|
bin | 10000011101100000110… |
… | …010000010101110111111 |
3 | 11000010211021121120221111 |
4 | 100131200302002232333 |
5 | 122013144213124413 |
6 | 2223355520342451 |
7 | 144504123312430 |
oct | 20354062025677 |
9 | 4003737546844 |
10 | 1131200129983 |
11 | 3a6814a8a490 |
12 | 163298774a27 |
13 | 828969aba51 |
14 | 3ca71077487 |
15 | 1e659b3dd3d |
hex | 10760c82bbf |
1131200129983 has 8 divisors (see below), whose sum is σ = 1410327434880. Its totient is φ = 881454646680.
The previous prime is 1131200129953. The next prime is 1131200130017. The reversal of 1131200129983 is 3899210021311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1131200129983 - 25 = 1131200129951 is a prime.
It is a super-2 number, since 2×11312001299832 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131200129903) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7345455313 + ... + 7345455466.
It is an arithmetic number, because the mean of its divisors is an integer number (176290929360).
Almost surely, 21131200129983 is an apocalyptic number.
1131200129983 is a deficient number, since it is larger than the sum of its proper divisors (279127304897).
1131200129983 is a wasteful number, since it uses less digits than its factorization.
1131200129983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14690910797.
The product of its (nonzero) digits is 23328, while the sum is 40.
The spelling of 1131200129983 in words is "one trillion, one hundred thirty-one billion, two hundred million, one hundred twenty-nine thousand, nine hundred eighty-three".
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