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11312001303 = 316323132927
BaseRepresentation
bin10101000100011111…
…10111000100010111
31002012100112012120020
422202033313010113
5141131333020203
65110251240223
7550215265431
oct124217670427
932170465506
1011312001303
11488536a009
122238449073
1310b3767bc5
147944c9651
1546316e153
hex2a23f7117

11312001303 has 8 divisors (see below), whose sum is σ = 15175200768. Its totient is φ = 7495068024.

The previous prime is 11312001301. The next prime is 11312001353. The reversal of 11312001303 is 30310021311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11312001303 - 21 = 11312001301 is a prime.

It is a super-2 number, since 2×113120013032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312001301) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11565975 + ... + 11566952.

It is an arithmetic number, because the mean of its divisors is an integer number (1896900096).

Almost surely, 211312001303 is an apocalyptic number.

11312001303 is a deficient number, since it is larger than the sum of its proper divisors (3863199465).

11312001303 is a wasteful number, since it uses less digits than its factorization.

11312001303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23133093.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11312001303 its reverse (30310021311), we get a palindrome (41622022614).

The spelling of 11312001303 in words is "eleven billion, three hundred twelve million, one thousand, three hundred three".

Divisors: 1 3 163 489 23132927 69398781 3770667101 11312001303