11312004023 has 4 divisors (see below), whose sum is σ = 11575073928. Its totient is φ = 11048934120.

The previous prime is 11312004001. The next prime is 11312004089. The reversal of 11312004023 is 32040021311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32040021311 = 61 ⋅525246251.

It is a cyclic number.

It is not a de Polignac number, because 11312004023 - 2¹⁶ = 11311938487 is a prime.

It is a super-2 number, since 2×11312004023² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11312003992 and 11312004010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312004623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131534888 + ... + 131534973.

It is an arithmetic number, because the mean of its divisors is an integer number (2893768482).

Almost surely, 2^11312004023 is an apocalyptic number.

11312004023 is a deficient number, since it is larger than the sum of its proper divisors (263069905).

11312004023 is an equidigital number, since it uses as much as digits as its factorization.

11312004023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 263069904.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 11312004023 its reverse (32040021311), we get a palindrome (43352025334).

The spelling of 11312004023 in words is "eleven billion, three hundred twelve million, four thousand, twenty-three".