Base | Representation |
---|---|
bin | 10000011101100001000… |
… | …010000100100111100001 |
3 | 11000010211120112002000210 |
4 | 100131201002010213201 |
5 | 122013201302111001 |
6 | 2223400150404333 |
7 | 144504204113262 |
oct | 20354102044741 |
9 | 4003746462023 |
10 | 1131204332001 |
11 | 3a681739a527 |
12 | 16329a0606a9 |
13 | 82897820553 |
14 | 3ca7184c969 |
15 | 1e65a1bddd6 |
hex | 107610849e1 |
1131204332001 has 32 divisors (see below), whose sum is σ = 1547350076160. Its totient is φ = 734652979200.
The previous prime is 1131204331993. The next prime is 1131204332009. The reversal of 1131204332001 is 1002334021311.
It is an interprime number because it is at equal distance from previous prime (1131204331993) and next prime (1131204332009).
It is not a de Polignac number, because 1131204332001 - 23 = 1131204331993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1131204332009) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 405302916 + ... + 405305706.
It is an arithmetic number, because the mean of its divisors is an integer number (48354689880).
Almost surely, 21131204332001 is an apocalyptic number.
It is an amenable number.
1131204332001 is a deficient number, since it is larger than the sum of its proper divisors (416145744159).
1131204332001 is a wasteful number, since it uses less digits than its factorization.
1131204332001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6537.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1131204332001 its reverse (1002334021311), we get a palindrome (2133538353312).
The spelling of 1131204332001 in words is "one trillion, one hundred thirty-one billion, two hundred four million, three hundred thirty-two thousand, one".
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