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113120434123 = 167677367869
BaseRepresentation
bin110100101011010000…
…0001101011111001011
3101210222120001110021021
41221112200031133023
53323132312342443
6123544455253311
711113141553014
oct1512640153713
9353876043237
10113120434123
1143a79599494
1219b0b97a237
13a889b2ab28
1456917ba00b
152e2102a9ed
hex1a5680d7cb

113120434123 has 4 divisors (see below), whose sum is σ = 113797802160. Its totient is φ = 112443066088.

The previous prime is 113120434003. The next prime is 113120434201. The reversal of 113120434123 is 321434021311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113120434123 - 221 = 113118336971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113120434223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 338683768 + ... + 338684101.

It is an arithmetic number, because the mean of its divisors is an integer number (28449450540).

Almost surely, 2113120434123 is an apocalyptic number.

113120434123 is a deficient number, since it is larger than the sum of its proper divisors (677368037).

113120434123 is an equidigital number, since it uses as much as digits as its factorization.

113120434123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 677368036.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 113120434123 its reverse (321434021311), we get a palindrome (434554455434).

The spelling of 113120434123 in words is "one hundred thirteen billion, one hundred twenty million, four hundred thirty-four thousand, one hundred twenty-three".

Divisors: 1 167 677367869 113120434123