113120441243101 has 4 divisors (see below), whose sum is σ = 114483338125632. Its totient is φ = 111757544360572.

The previous prime is 113120441243053. The next prime is 113120441243167. The reversal of 113120441243101 is 101342144021311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113120441243101 - 2³¹ = 113118293759453 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113120441243101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113120441243501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 681448441141 + ... + 681448441306.

It is an arithmetic number, because the mean of its divisors is an integer number (28620834531408).

Almost surely, 2^{113120441243101} is an apocalyptic number.

It is an amenable number.

113120441243101 is a deficient number, since it is larger than the sum of its proper divisors (1362896882531).

113120441243101 is an equidigital number, since it uses as much as digits as its factorization.

113120441243101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1362896882530.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 113120441243101 its reverse (101342144021311), we get a palindrome (214462585264412).

The spelling of 113120441243101 in words is "one hundred thirteen trillion, one hundred twenty billion, four hundred forty-one million, two hundred forty-three thousand, one hundred one".