Base | Representation |
---|---|
bin | 110100101011010001… |
… | …0010111101100011111 |
3 | 101210222121010012210221 |
4 | 1221112202113230133 |
5 | 3323132434001343 |
6 | 123544515342211 |
7 | 11113146431320 |
oct | 1512642275437 |
9 | 353877105727 |
10 | 113121000223 |
11 | 43a79945840 |
12 | 19b0bbb1967 |
13 | a889c986ba |
14 | 56918c6447 |
15 | 2e210dd5ed |
hex | 1a56897b1f |
113121000223 has 8 divisors (see below), whose sum is σ = 141033974400. Its totient is φ = 88146233880.
The previous prime is 113121000221. The next prime is 113121000227. The reversal of 113121000223 is 322000121311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113121000223 - 21 = 113121000221 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113121000197 and 113121000206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113121000221) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 734551873 + ... + 734552026.
It is an arithmetic number, because the mean of its divisors is an integer number (17629246800).
Almost surely, 2113121000223 is an apocalyptic number.
113121000223 is a deficient number, since it is larger than the sum of its proper divisors (27912974177).
113121000223 is a wasteful number, since it uses less digits than its factorization.
113121000223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1469103917.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 113121000223 its reverse (322000121311), we get a palindrome (435121121534).
The spelling of 113121000223 in words is "one hundred thirteen billion, one hundred twenty-one million, two hundred twenty-three", and thus it is an aban number.
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