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11312101111 = 23474819813
BaseRepresentation
bin10101000100100000…
…01111011011110111
31002012100201021110211
422202100033123313
5141131344213421
65110253330251
7550216162423
oct124220173367
932170637424
1011312101111
114885427aa3
122238496987
1310b37a146c
14794513b83
1546318d9e1
hex2a240f6f7

11312101111 has 4 divisors (see below), whose sum is σ = 11316923272. Its totient is φ = 11307278952.

The previous prime is 11312101091. The next prime is 11312101133. The reversal of 11312101111 is 11110121311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11312101111 - 213 = 11312092919 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11312101091 and 11312101100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312101181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2407560 + ... + 2412253.

It is an arithmetic number, because the mean of its divisors is an integer number (2829230818).

Almost surely, 211312101111 is an apocalyptic number.

11312101111 is a deficient number, since it is larger than the sum of its proper divisors (4822161).

11312101111 is an equidigital number, since it uses as much as digits as its factorization.

11312101111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4822160.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 11312101111 its reverse (11110121311), we get a palindrome (22422222422).

The spelling of 11312101111 in words is "eleven billion, three hundred twelve million, one hundred one thousand, one hundred eleven".

Divisors: 1 2347 4819813 11312101111