11312124322041 has 16 divisors (see below), whose sum is σ = 16758763848000. Its totient is φ = 7541388697824.

The previous prime is 11312124322027. The next prime is 11312124322117. The reversal of 11312124322041 is 14022342121311.

11312124322041 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 21 + 2 + 432 + 204 + 1 = 666.

It is not a de Polignac number, because 11312124322041 - 2¹³ = 11312124313849 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 11312124321996 and 11312124322014.

It is not an unprimeable number, because it can be changed into a prime (11312124322021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9075610 + ... + 10246508.

It is an arithmetic number, because the mean of its divisors is an integer number (1047422740500).

Almost surely, 2^{11312124322041} is an apocalyptic number.

It is an amenable number.

11312124322041 is a deficient number, since it is larger than the sum of its proper divisors (5446639525959).

11312124322041 is a wasteful number, since it uses less digits than its factorization.

11312124322041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1528725 (or 1528719 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 11312124322041 its reverse (14022342121311), we get a palindrome (25334466443352).

It can be divided in two parts, 1131212 and 4322041, that added together give a triangular number (5453253 = T₃₃₀₂).

The spelling of 11312124322041 in words is "eleven trillion, three hundred twelve billion, one hundred twenty-four million, three hundred twenty-two thousand, forty-one".