Base | Representation |
---|---|
bin | 1010010010011100111100… |
… | …1001101110000101000101 |
3 | 1111001102120101122002021211 |
4 | 2210213033021232011011 |
5 | 2440314212311301432 |
6 | 40020415043011421 |
7 | 2245162662144613 |
oct | 244471711560505 |
9 | 44042511562254 |
10 | 11312124322117 |
11 | 3671499300933 |
12 | 1328447669b71 |
13 | 640962095758 |
14 | 2b171ca186b3 |
15 | 1493c3494d47 |
hex | a49cf26e145 |
11312124322117 has 2 divisors, whose sum is σ = 11312124322118. Its totient is φ = 11312124322116.
The previous prime is 11312124322027. The next prime is 11312124322133. The reversal of 11312124322117 is 71122342121311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8431072984161 + 2881051337956 = 2903631^2 + 1697366^2 .
It is a cyclic number.
It is not a de Polignac number, because 11312124322117 - 223 = 11312115933509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312124352117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656062161058 + 5656062161059.
It is an arithmetic number, because the mean of its divisors is an integer number (5656062161059).
Almost surely, 211312124322117 is an apocalyptic number.
It is an amenable number.
11312124322117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312124322117 is an equidigital number, since it uses as much as digits as its factorization.
11312124322117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4032, while the sum is 31.
Adding to 11312124322117 its reverse (71122342121311), we get a palindrome (82434466443428).
The spelling of 11312124322117 in words is "eleven trillion, three hundred twelve billion, one hundred twenty-four million, three hundred twenty-two thousand, one hundred seventeen".
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