Base | Representation |
---|---|
bin | 110100101011010001… |
… | …1100001001000010101 |
3 | 101210222121200111102022 |
4 | 1221112203201020111 |
5 | 3323133023113023 |
6 | 123544530022525 |
7 | 11113152123260 |
oct | 1512643411025 |
9 | 353877614368 |
10 | 113121301013 |
11 | 43a7a030826 |
12 | 19b10117a45 |
13 | a88a072596 |
14 | 5691963cd7 |
15 | 2e2114c7c8 |
hex | 1a568e1215 |
113121301013 has 4 divisors (see below), whose sum is σ = 129281486880. Its totient is φ = 96961115148.
The previous prime is 113121301001. The next prime is 113121301021. The reversal of 113121301013 is 310103121311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 113121301013 - 26 = 113121300949 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113121300982 and 113121301000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113121301913) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8080092923 + ... + 8080092936.
It is an arithmetic number, because the mean of its divisors is an integer number (32320371720).
Almost surely, 2113121301013 is an apocalyptic number.
It is an amenable number.
113121301013 is a deficient number, since it is larger than the sum of its proper divisors (16160185867).
113121301013 is an equidigital number, since it uses as much as digits as its factorization.
113121301013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16160185866.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113121301013 its reverse (310103121311), we get a palindrome (423224422324).
The spelling of 113121301013 in words is "one hundred thirteen billion, one hundred twenty-one million, three hundred one thousand, thirteen".
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